In the reaction h2so4 + 2 naoh -> na2so4 + 2h2o, an equivalence point occurs when 28.54 ml of 0.2075 m naoh is added to a 34.23 ml portion of h2so4. what is the [h2so4]?

            moles NaOH = c · V = 0.2075 mmol/mL · 28.54 mL = 5.92205 mmol
            moles H2SO4 = 5.92205 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 2.961025 mmol
Hence
            [H2SO4]= n/V = 2.961025 mmol / 34.23 mL = 0.08650 M
The answer to this question is  [H2SO4] = 0.08650 M

Idon't know hope someone you