Darin skateboarded to the north at 4 m/s. in 5 seconds, he sped up to 7 m/s. what was his acceleration? a. -0.6 m/s2 north b. -1.66 m/s2 north c. 0.6 m/s2 north d. 1.66 m/s2 north

To solve this problem we can use following equation.

v =u + at

Where v is the final velocity (m/s), u is the initial velocity (m/s), a is the acceleration (m/s²) and t is the time taken (s).

v = 7 m/s
u = 4 m/s
a = ?
t = 5 s

By applying the equation, we can get
    7 m/s = 4 m/s + a x 5 s
    3 m/s = a x 5 s
          a = 0.6 m/s²

Hence, the acceleration is 0.6 m/s² towards north.

Answer is "C".

H2so4 is the chemical compound of sulfuric acid. 

Its carbonyl