In the reaction mg (s) + 2hcl (aq) h2 (g) + mgcl2 (aq), how many moles of hydrogen gas will be produced from 75.0 milliliters of a 1.0 m hcl in an excess of mg? 0.75 moles 1.0 moles 0.038 moles 0.075 moles

The answer is .038 because it rounded from .0375 to .038

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !