For a titration of 25 ml of naoh solution, 23.30 ml of hcl solution if used. what is the molarity of naoh

HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)

As you can see here, one mole of acid neutralizes one mole of base.

We use the concentration equation, which states that,

c=nv

Rearranging for moles, we get,

n=c⋅v

So, we have:

nNaOH=0.1 M⋅0.05 L

=0.005 mol

Since one mole of acid neutralizes one mole of base, then we must have: nHCl=nNaOH.

And so,

cHCl=nHClvHCl

=0.005 mol0.03 L

≈0.17 M

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation:

particle   p is an electron and particle q is a neutron