Compute the specific heat capacity at constant volume of nitrogen (n2) gas. the molar mass of n2 is 28.0 g/mol. c = j/(kg⋅k) request answer part b you warm 1.30 kg of water at a constant volume from 22.0 ∘c to 28.5 ∘c in a kettle. for the same amount of heat, how many kilograms of 22.0 ∘c air would you be able to warm to 28.5 ∘c? make the simplifying assumption that air is 100% n2. m = kg request answer part c what volume would this air occupy at 22.0 ∘c and a pressure of 1.10 atm ?

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole