To 225ml of a 0.80m solution of ki, a student adds enough water to make 1.0 l of a more dilute ki solution. what is the morality of the new solution?

We use the the dilution equation expressed as
     M1V1 = M2V2
where the terms with subscripts of one represent the initial conditions for the concentrated solution while the terms with subscripts of two represent the final conditions for the diluted solution. 
Rearranging the dilution formula to calculate for the molarity M2 of the diluted solution
     M2 = M1V1 / V2 = (0.80M * 0.225L) / 1.0L = 0.18 M

Rn in the right answer

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