Asample of 54.0 g of methanol is heated from 25.0 °c to 35.0 °c. how much heat is required? the specific heat capacity of methanol is 2.48 j g–1 k–1.

The  amount of heat required   is calculated  using the below  formula

Q(heat) =M(mass) xC(specific heat capacity)x delta T (change in temperature)

change in the temperature in kelvin=(35+273)- (25 +2730= 10K
c= 2.48 j/g/k
mass= 54.0 g

Q= 54.0 g x 2.48 j/g/k x 10k  = 1339.2  joules is required

The gas would begin to expand, and eventually the can would burst or explode.