What volume of chlorine is required to produce 25.4?

From this reaction equation:

Cu + Cl2 → CuCl2

so 1 mol CuCl2 will produce from 1 mol Cl2

when the moles of CuCl2 = mass / molar mass 

                                            = 25.4 g / 134.45 g/mol

                                            = 0.189 moles 

∴0.189 moles of CuCl2 will produce from 0.189 moles Cl2

∴ Volume of 0.189 moles of Cl2 is :

 V = nRT/P

when n is the number of moles = 0.189 moles

R is ideal gas constant = 0.0821 

T temperature in Kelvin = 18 + 273 = 291 K

P is the pressure = 2.13 atm

by substitution:

∴ V = 0.189 * 0.0821 * 291 / 2.13

    = 2.12 L

I’d have to say no because without oxygen in the water the fish would all be dead. so if you want to fish for dead fish, pick the ponds with the lowest oxygen concentrations.