50.0 ml of an hno3 solution were titrated with 36.90 ml of a 0.100 m lioh solution to reach the equivalence point. what is the molarity of the hno3 solution

Following reaction takes place between LiOH and HNO3

LiOH    +  HNO3        →        LiNO3      +       H2O

Thus, 1 mole of LiOH reacts with 1 mole of HNO3 to form 1 mole of LiNO3.

Now, 
Number of millimoles of LiOH consumed = 36.90 X 0.100 = 3.690

∴Number of millimoles of HNO3 present = 3.690

Now, Molarity of HNO3 = 
                                      =    = 0.0738 M

Thus, molarity of the HNO3 solution is 0.0738 M

Sorry i dont understand the question can you rephase it?