You have a 5l of a 5m solution of an acid. what is the resulting molarity if you mix 8 l of a base? (use: m1v1=m2v2)

Using dilution equationm1v1 =m2v2 ; where m1 and m1 are the intiial and final concentration, and v1 and v2 are the initial and final volume.5  × 5 m = 8 l  × m2m2 = 25/8 = 3.125 mtherefore; the resulting molarity is 3.125 m

Hey how did you manage to type such a big lab report