What is the rate of a reaction if the value of k is 0.01, [a] is 2 m, and [b] is 3 m? rate = k[a]3[b]2

Rate equation for the reaction is as follows
Rate = k [A]³[B]²
concentration of A = 2 M
concentration of B = 3 M
k - rate constant - 0.01
as this is a 5th order reaction, units for rate constant are M⁻⁴s⁻¹
substituting these values in the equation 

Rate = k [A]³[B]²
rate = 0.01 M⁻⁴s⁻¹ x (2 M)³ x (3 M)²
rate = 0.01 x 8 x 9 = 0.72
rate of the reaction is 0.72 M/s

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