Chemistry, 20.07.2019 19:00 jakhunter354

What is the maximum number of grams of silver phosphate that can be produced from the reaction of 287g of silver chlorate with 52.8g of sodium phosphate? 3 ag(clo3) + na3(po4) —> 3 na(clo3) + ag3(po4)

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The balanced equation for the above reaction is as follows;
3AgClO₃ + Na₃PO₄ ---> Ag₃PO₄ + 3NaClO₃
stoichiometry of AgClO₃ to Na₃PO₄ is 3:1
first we need to find which is the limiting reactant

number of AgClO₃ moles - 287 g / 191.3 g/mol = 1.500 mol
number of Na₃PO₄ moles - 52.8 g / 163.9 g/mol = 0.322 mol
if AgClO₃ is the limiting reactant
then 1.500 mol of AgClO₃ reacts with - 1.500/3 mol of Na₃PO₄
therefore number of Na₃PO₄ moles required = 0.50 mol of Na₃PO₄ are required but only 0.322 mol are present
therefore Na₃PO₄ is the limiting reactant
amount of product formed depends on amount of limiting reactant present
stoichiometry of Na₃PO₄ to Ag₃PO₄ is 1:1
the number of Na₃PO₄ moles reacted - 0.322 mol
then number of Ag₃PO₄ moles formed - 0.322 mol
mass of Ag₃PO₄ formed - 0.322 mol x 418.6 g/mol = 134.8 g
mass of Ag₃PO₄ produced is 134.8 g

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

it's filtration, but this is an assumption so my apologies if i got this

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