Ammonia (nh3(g), es001-1.jpghf = –46.19 kj/mol) reacts with hydrogen chloride (hcl(g), es001-2.jpghf = –92.30 kj/mol) to form ammonium chloride (nh4cl(s), es001-3.jpghf = –314.4 kj/mol) according to this equation: nh3(g) + hcl(g) es001-4.jpg nh4cl(s) what is es001-5.jpghrxn for this reaction? kj

i don,t know so just answer mine

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.