Gundy Company expects to produce 1,272,000 units of Product XX in 2020. Monthly production is expected to range from 85,000 to 129,000 units. Budgeted variable manufacturing costs per unit are direct materials $3, direct labor $6, and overhead $9. Budgeted fixed manufacturing costs per unit for depreciation are $6 and for supervision are $1. Prepare a flexible manufacturing budget for the relevant range value using 22,000 unit increments

Security a has a higher standard deviation of returns than security b. we would expect that: (i) security a would have a risk premium equal to security b. (ii) the likely range of returns for security a in any given year would be higher than the likely range of returns for security b. (iii) the sharpe ratio of a will be higher than the sharpe ratio of b. (a) i only (b) i and ii only (c) ii and iii only (d) i, ii and iii

Lambert manufacturing has $100,000 to invest in either project a or project b. the following data are available on these projects (ignore income taxes.): project a project b cost of equipment needed now $100,000 $60,000 working capital investment needed now - $40,000 annual cash operating inflows $40,000 $35,000 salvage value of equipment in 6 years $10,000 - both projects will have a useful life of 6 years and the total cost approach to net present value analysis. at the end of 6 years, the working capital investment will be released for use elsewhere. lambert's required rate of return is 14%. the net present value of project b is:

Bayside coatings company purchased waterproofing equipment on january 2, 20y4, for $190,000. the equipment was expected to have a useful life of four years and a residual value of $9,000. instructions: determine the amount of depreciation expense for the years ended december 31, 20y4, 20y5, 20y6, and 20y7, by (a) the straight-line method and (b) the double-declining-balance method. also determine the total depreciation expense for the four years by each method. depreciation expense year straight-line method double-declining-balance method 20y4 $ $ 20y5 20y6 20y7 total $