Assume that electricity costs $0.06 per kilowatt-hour, the projects are both repeatable, and that Soumya uses a MARR of 8% per year. Neither pump retains any salvage value at the end of its lifetime. Recall that 1 hp = 0.746 kW. Efficiency defines what percentage of the power drawn from the power outlet is actually converted to useful output. As a result, both pumps deliver 60 hp of useful output, but Motor A will consume more electricity because it is less efficient. What is the annual worth of the costs associated with the preferred option? Express your answer as a positive value, rounded to the nearest dollar.