A+b-c =170 B+c-A= 130
solve

The solutions to the system of equations is A = 20, B = 150 and C = 0

The equations are given as:

Subtract the second equation from the first equation

Open brackets

Collect like terms

Divide both sides by 2

Add both equations

Remove bracket

Collect like terms

Divide both sides by 2

Substitute 150 for B and 20 for A in

Subtract 170 from both sides

Hence, the solutions to the system of equations is A = 20, B = 150 and C = 0

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The correct answer is A = 110, B= 40, C=20..

Explanation

If A+B-C= 170 and B+C-A=130 ,  

=C+A = 130

or, C= 130- A

Again, A+B-C =170

or, A+B =170+C

A+B = 170+130-A ( c=130-A)

A+B = 300-A

2A+B = 300

A+B= 300/2

A+B = 150

A+B-C= 170

A+B = 170+C

150 = 170 +C ( A+B = 150)

or, C = 20(1.)

A+C =130

or,A+ 20= 130 ( A=110)(2)

A+B = 150

110+B= 150

B = 150-110

B= 40(3)

Therefore, A = 110, B= 40, C=20..

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