Suppose there are two types of tickets to a show: advanced and same-day. The combined cost of one advance ticket and one same-day ticket is $ 60 . For one performance, 20 advance tickets were sold, and 40 same-day tickets were sold. The total amount paid for these tickets was $ 1700 . What was the price for each kind of ticket?

Price of advance ticket = $35,  Price of same-day ticket = $25

Explanation:

Given:

There are two types of tickets to a show; advanced and same-day.

The combined cost of one advance ticket and one same-day ticket is $ 60 .

For one performance, 20 advance tickets and 40 same-day tickets were sold for $ 1700.

Question asked:

What was the price for each kind of ticket?

Solution:

Let price of each advance ticket =

As combined cost of one advance ticket and one same-day ticket is $ 60.

Hence, the price of each same-day ticket =

As given that for one performance, 20 advance tickets and 40 same-day tickets were sold for total $ 1700, the equation will be:-

Subtracting both sides by 2400

Adding both sides by minus

Dividing  both sides by 20

The price of each advance ticket = = $35

The price of each same-day ticket = = 60 - 35 = $25

Therefore,

The price of each advance ticket is $35 and of each same-day ticket is $25.

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explanation:

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