Achemical company makes two brands of antifreeze. the first brand is 40%pure antifreeze, and the second brand is 90%pure antifreeze. in order to obtain 180gallons of a mixture that contains 55%pure antifreeze, how many gallons of each brand of antifreeze must be used?

1st brand is 126 gallons

ans 2nd brand = 54 gallons

Explanation:

given data

first brand = 40%

second brand = 90%

mixture =  55%

mixture = 180 gallons

to find out

how many gallons of each brand

solution

we consider here 1st brand is = x and 2nd brand is y

so on mixing we get

total volume = x + y    ...............1

put here value

180 = x + y    .................2

and mixing equation will be

40 x + 90 y = 55 ( x+ y)

solve it we get

3 x = 7 y

x = y    ........................3

put equation 3 in equation 2

180 = y  + y  

solve it we get

y = 54

and  now put in equation 2 we get

180 = x + 54

x = 126

so

1st brand is 126 gallons

ans 2nd brand = 54 gallons

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