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Business, 11.11.2019 18:31 htx88

Paul was asked to use the elmination to find the solution to the system of linear equations 5x + 4y = 1 βˆ’2x βˆ’ 8y = βˆ’26 what are the missing steps in his work below? 5x + 4y = 1 βˆ’2x βˆ’ 8y = βˆ’26 10x + 8y = 2 + (βˆ’2x βˆ’8y = βˆ’26) 8x + 0y = βˆ’24 8x = βˆ’24 x = βˆ’3 5x + 4y = 1 5(βˆ’3) + 4y = 1 βˆ’15 + 4y = 1 4y = 16 y = 4 select one: a. 5x + 4y = 1 + (βˆ’2x βˆ’ 8y = βˆ’26) b. 2β‹…[5x + 4y = 1] 10x + 8y = 2 c. 5x + 4y = 1 βˆ’ (βˆ’2x βˆ’ 8y = βˆ’26) d. βˆ’5β‹…[βˆ’2x βˆ’ 8y = βˆ’26] 10x + 40y = 130

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Paul was asked to use the elmination to find the solution to the system of linear equations 5x + 4y...
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