When interest is compounded continuously, the amount of money increases at a rate proportional to the amount s present at time t, that is, ds/dt = rs, where r is the annual rate of interest. (a) find the amount of money accrued at the end of 5 years when $4000 is deposited in a savings account drawing 5 3 4 % annual interest compounded continuously. (round your answer to the nearest cent.) $ (b) in how many years will the initial sum deposited have doubled? (round your answer to the nearest year.) years (c) use a calculator to compare the amount obtained in part (a) with the amount s = 4000 1 + 1 4 (0.0575) 5(4) that is accrued when interest is compounded quarterly. (round your answer to the nearest cent.) s = $

a) - r=5%:

- r=4%:

- r=3%:

b) - r=5%: t=14 years

- r=4%: t=17 years  [/tex]

- r=3%: t=23 years  [/tex]

c) The amount obtained is

- Compuonded quarterly: $5,191.83

- Compuonded continously: $5,200.71

The latter is always greater, since the more often it is capitalized, the greater the effect of compound interest and the greater the capital that ends up accumulating.

Explanation:

The rate of accumulation of money is

To calculate the amount of money accumulted in a period, we have to rearrange and integrate:

When t=0, S=S₀ (the initial capital).

Now we have the equation for the capital in function of time:

a) For an initial capital of $4000 and for a period of five years, the amount of capital accumulated for this interest rates is:

- r=5%:

- r=4%:

- r=3%:

b) We can express this as

- r=5%:

- r=4%:

- r=3%:

c) When the interest is compuonded quarterly, the anual period is divided by 4. In 5 years, there are 4*5=20 periods of capitalization. The annual rate r=0.0525 to calculate the interest is also divided by 4:

If compuonded continously, we have:

The amount obtained is

- Compuonded quarterly: $5,191.83

- Compuonded continously: $5,200.71

The latter is always greater, since the more often it is capitalized, the greater the effect of compound interest and the greater the capital that ends up accumulating.

answer; ///deficit;