Weebee company has three assembly labor classifications: s-1, s-2, and s-3. the three classifications are paid $16, $19, and $22 per hour, respectively. the assembly activity for a product uses an s-2 employee who performs that task in 24 minutes. to reduce the activity cost per unit, a product engineer proposes using a higher-rated employee who can perform the assembly in 21 minutes. a manager proposes using a lower-rated employee who can perform the assembly in 30 minutes. which of the following provides the most cost-effective solution?
a. use the s-1 employeeb. use the s-2 employeec. use the s-3 employeed. use either the s-1 or s-3 employee

The answer is: B) use the S-2 employee

Explanation:

If you use an S-2 employee to make one unit of the product you are going to spend $7.60 [(24 min / 60 min) x $19].

If you use an S-1 employee to make one unit of the product you are going to spend $8.00 [(30 min / 60 min) x $16].

If you use an S-3 employee to make one unit of the product you are going to spend $7.70 [(21 min / 60 min) x $22].

Using an S-2 employee is the cheapest; $7.60.

the investment was $14,174.196

explanation:

a lump sum means that the father of the example made one deposit and leave it be.

we need to know the value of a capital that generated at 4.05% per year during 28 years the sum of $48,613.24

now clearing the formula to solve for capital we got:

and we reach the answer investment = $14,174.20

answer; the landlord can sue the renter,and the renter loses the security deposit;