Albinism is inherited as a simple recessive trait. if a woman and her husband are both heterozygous for albinism then what is the probability that their first five children will have these phenotypes? child 1 - albino; child 2 - normal; child 3 - normal; child 4 - albino; child 5 - normal?

Albinism is recessive trait so you need both genes(homozygous recessive) to develop it. If both of the parent is heterozygous the genotype of the children would be:
25% homozygous dominant(normal)
50% heterozygous (normal)
25% homozygous recessive(albino)
You can conclude that there is 25% or 1/4 chance of the offspring become albino while 3/4 chance they become normal. Assuming the order of the offspring is important, the chance would be:

albino * normal * normal * albino * normal= 1/4 * 3/4 * 3/4 * 1/4 * 3/4= 27/1024

Ithink the answer is d.

This is the most closely resembles the model.