Which molecule is regenerated in the regeneration phase of the calvin cycle? without regeneration of this molecule, the calvin cycle would stop?

RuBP is regenerated in the regeneration phase of the calvin cycle without regeneration of this molecule, the calvin cycle would stop. Ribulose bisphosphate (RuBP) is a 5 carbon compound included in the Calvin cycle, which is a section of the light-independent reactions of photosynthesis. Atmospheric carbon dioxide (CO2) is combined with RuBP to make a 6 carbon compound with the help of Rubisco which is an enzyme.

A RuBP molecule is regenerated in the regeneration phase of the Calvin cycle and without RuBP Calvin cycle would stop.

Further Explanation:

Calvin cycle occur in C-3 plants that is used for the reaction of photosynthesis. It is the light dependent reactions which is used to produced glucose and carbohydrate. This reaction acquires energy stored by the light. Calvin cycle is categorized into three basic steps; fixation, reduction regeneration and fixation.

In the stroma of the plant, two chemicals are also present other than carbon dioxide that helps in initiating the Calvin cycle. These enzymes are RuBisCo and RuBP. RuBP is the five atom carbon chain with two phosphate group attached on each end. RuBisCo is the important enzyme which is used to catalyze a reaction in middle of carbon dioxide and RuBP which helps in carbon fixation by producing two three carbon compound from 6 carbon compound.

Calvin cycle require six complete turns to fix six carbon atom from carbon dioxide. The complete processes utilize twelve ATP and twelve NADPH molecules in the reduction step and other six ATP molecules for the regeneration process. Glucose 3 phosphate is the compound used for RuBP regeneration.

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Answer Details:

Grade: High School

Subjects: Biology

Topic: Photosynthesis

Keywords:

Calvin, RuBP, photosynthesis, glucose, carbohydrate, energy, fixation, reduction, regeneration, stroma, chemicals, RuBisCo, ATP, NADPH, glucose 6 phosphate.

i think its c. amphipod

true is the final answer!