It contains a bamh1 site (g^gatcc) and a bglii site (a^gatct). in order for the synthetic gene to be inserted between these two sites, it should be constructed to have which restriction sites at its beginning and at its end? select all that apply.

The answers are:

BamH1 (G^GATCC), followed by BamH1 (G^GATCC)

BamH1 (G^GATCC), followed by BglII (A^GATCT)

BglII (A^GATCT), followed by BglII (A^GATCT)

Since the similar sticky ends are made by both BamH1 and BglII sites can be positioned at both ends of the synthetic gene. DNA fragments made by the same enzyme can permanently be ligated.

the father in the first generation probably had the recessive colorblind trait in his x chromosome. if he and his wife both had the colorblind trait, even if she had 1 recessive and 1 dominant, then that trait would be passed on to their kids.

(since you didn't attach the family tree this is just an assumption)

answer; /// the correct )