The punnett square shows the possible genotype combinations of two parents who are heterozygous for a particular trait. what is the probability of the parents having a child who is homozygous dominant for this trait? 0% 25% 50% 75%

The probability of the parents having a child who is hzygous dominant for this trait is - 25%

In the given question, there is a particular character that has two alleles Y dominant allele and y recessive allele. Both parents are heterozygous for the trait that is encoded as Yy cross with Yy.

        (1/4)*100

        = 25%

Thus, the correct probability would be - 25%

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Based on the laws of probability, the probability of the having a child who is h0m0zygous dominant for the trait indicated in the Punnet square is 25%.

Assuming the dominant trait is Y and the recessive trait is y.

From the Punnet square, the offspring genotype are: YY, Yy, Yy and yy.

The child having h0m0zygous dominant trait is YY.

Probability = 1/4 = 25%.

Therefore, the probability of the having a child who is h0m0zygous dominant for the trait indicated in the Punnet square is 1/4 or 25%.

Learn more about about probability at: link

uh two lol

the corpus luteum secretes estrogens and progesterone. the latter hormone causes changes in the uterus that make it more suitable for implantation of the fertilized ovum and the nourishment of the embryo. if the egg is not fertilized, the corpus luteum becomes inactive after 10–14 days, and menstruation occurs.

i hope this : )