Given a population of 100 individuals where 15 are AA, 25 are Aa, and 60 are aa, what is the frequency of allele “A” and the frequency of allele “a”?

frequency of allele “A” is .39

frequency of allele “a” is .77

Explanation:

hardy weinberg equation

p^2 + 2pq + q^2 = 1 or (A+a)^2

p^2=  (AA)

2pq=  (Aa)

q^2=(aa)

AA -> 15/100 = .15

Aa -> 25/100 = .25

aa -> 60/100 = .60

if p^2 = AA = .15 then A = √.15 = 0.38729833462 = .39

if q^2 = aa = .60 then a = √.60 = 0.77459666924 = .77

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explanation:

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