5 puntos 5. Si el color de ojos negros es dominante (A) sobre el color de ojos azul
(a). El fenotipo y el genotipo que tendríamos al cruzar dos personas
heterocigotas es
*
GENOTIPO: 50% Heterocigotas - 25% homocigotas dominantes - 25% homocigotas
recesivas. FENOTIPO: 75% ojos negros - 25% ojos azules
GENOTIPO: 100% Heterocigotas. FENOTIPO: 100% ojos negros.
GENOTIPO: 50% Heterocigotas - 50% homocigota recesivo. FENOTIPO: 100% ojos
negros.
GENOTIPO: 50% Heterocigotas - 50% homocigotas dominantes FENOTIPO: 50% ojos
negros - 50% ojos azules

it enhances antibody production by t cells of the adaptive immune system.

hope i'm right

explanation:

we solve the problem using the hardy-wineberg equation.

let us start with the homozygous recessive proportion of individuals with sickle cell anaemia,

we have the proportion as q² = 0.25.

∴ q = 0.5 (frequency of hbs in population)

further,

solving for the frequency of normal cell by using the fact that,

p + q = 1

∴ p = 1 - 0.5 = 1 - 0.5 = 0.5

now we can calculate 2pq in p² + 2pq + q², which is the frequency for heterozygous carriers of sickle cell anaemia,

∴ 2pq = 2 x 0.5 x 0.5 = 0.5

and the homozygous normal cell individuals proportion is given by the expression,

∴ p² = 0.5² = 0.25

hence, the carriers for sickle cell anaemia are in proportion, 0.5, or 50%.