How high is the ceiling in a school gym if a volleyball thrown upward from the floor at 15 m/s barely touches the ceiling before returning to the ground?

The height of the ceiling in the school gym from the floor is 11.48m.

HOW TO CALCULATE HEIGHT OF A PROJECTILE:

v² = u² + 2as

Where;

v = final velocity (m/s)

u = initial velocity (m/s)

a = gravitational acceleration (m/s²)

s = distance traveled (m)

According to this question,

Using the formula, v² = u² + 2as, the height of the ceiling (s) can be calculated as follows:

15² = 0² + 2 (9.8) (s)

225 = 0 + 19.6s

225 = 19.6s

s = 225/19.6

s = 11.48m

Therefore, the height of the ceiling in the school gym from the floor is 11.48m

Learn more:

11.47 m

Explanation:

Givens

vi =   15 m/s

a = - 9.81 m/s^2

vf = 0

d = ?

Formula

vf^2 = vi^2 + 2ad

Solution

0 = (15)^2 + 2*(-9.81)*d

- 225 = 2 * - 9.81 *d

-225 = - 19.62 * d

d = - 225/-19.62

d = 11.47 m

the electromagnetic energy from the sun arrives in the form of visible and invisible light.

a) carbon, hydrogen

b) carbon, hydrogen, oxygen, nitrogen

c) carbon, hydrogen, oxygen, nitrogen, phosphorus

d) sugar

e) amino acid

f) nucleotide