Suppose that the concentration of Na outside the cell is 100 and inside the cell is 10 mmol/liter. The Nernst equation at 20oC is: You set the membrane voltage at 58 millivolts using a voltage clamp, and measure membrane current. If Na is the only ion crossing the membrane, you would expect to see: Group of answer choices

Complete question:

Suppose that the concentration of Na+ outside the cell is 100 and inside the cell is 10 mmol/liter. The Nernst equation at 20oC is:

Eion = 58 millivolts/z. [Log₁₀ (C-out/C-in)

You set the membrane voltage at +58 millivolts using a voltage clamp, and measure membrane current. If Na+ is the only ion crossing the membrane, you would expect to see:

a) 0 current

b) positive charges flowing into the cell

c) negative charges flowing into the cell

d) the membrane voltage becomes more positive

b) positive charges flowing into the cell

Explanation:

Nernst equation:

E = 58 millivolts/z. [Log₁₀ (C-out/C- in)

Where,

The bigger concentration value places in the numerator and the smaller concentration value laces in the denominator.  

Now let us see the provided values,

E = 58 millivolts/z. [Log₁₀ (Ion out/Ion i)

E = 58 millivolts/+1. [Log₁₀ (100mmol/liter / 10 mmol/liter)

E = 58 millivolts (Log₁₀ 10)

E = 58 millivolts (1)

E = 58 millivolts

58 mV is the absolute value of equilibrium potential.

Due to the differences in concentration, and being the only ion crossing the membrane, Na+ diffuses from outside -which is the highest concentration side- to the interior of the cell -which is the lowest concentration side-. Positive charges are moving into the cell. The interior of the cell becomes more positive.

during the process of dna replication, brdu can replace thymidine and incorporate into the newly synthesized dna, cell proliferation thus can be reflected in the extent of brdu incorporation.

they dont have any evidence