Please I really need a help here ASAP. It's a physics question. A space ship travels 3.00 ~ 10 km vertically to transport scientists from one particular station to
another. After the transportation, the captain decides to go hizontally 2.00 * 10km to visit an Orie
Calculate its:
a. Distance
b. Displacement​

a).Don't know if you meant to write 3x10^10km and 2x10^10km

I'll solve with this... If they aren't the values... You can then input the real values.

Distance = Total length traveled.

D= 3x10^10 + 2x10^10

D= 5x10^10Km

b) Displacement:

Since it went vertically... Then went horizontally in the second phase... It is forming a right angled Triangle and the Displacement would be the Hypotenuse of this triangle.

Disp.= √ (3x10^10)²+(2x10^10)²

Disp.=3.61x10^10km.

stratosphere: as the altitude increases, the air temperature increases. the stratosphere has a layer of ozone, called the ozone layer. this layer absorbs most of the ultraviolet radiation from sunlight. this results in the stratosphere being warmer.

lysosomes contain a variety of enzymes, enabling the cell to break down various biomolecules it engulfs, including peptides, nucleic acids, carbohydrates, and lipids (lysosomal lipase). the enzymes responsible for this hydrolysis require an acidic environment for optimal activity. hope i !