In a lever, 120 N load is attached at a distance of 20 cm from the fulcrum. If this effort is used to lift 50 kg weight then, the load distance is:!?​

The load distance is 4.9 cm

Explanation:

Given;

Effort applied to the lever, E = 120 N

Load overcame by the effort, L = 50 kg = 50 x 9.8 = 490 N

distance of the effort from the fulcrum, e = 20 cm

let the distance of the load from the fulcrum = d

The following simple set-up is used to illustrate this lever;

  Δ

 ↓          20cm                             d                   ↓

120 N                                                                490 N

Lever operates on the principle of moment, so take moment about the pivot (fulcrum);

490(d) = 120(20)

d = (120 x 20) / (490)

d = 4.9 cm

Therefore, the load distance is 4.9 cm

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the correct answer is b