PLEASE HELP ASAP 5. An observable trait in a sexually reproducing plant species is controlled by a single gene that has only two alleles. The table below shows the allele frequencies of the dominant allele (P) and the recessive allele (p) over five generations:

Generation Frequency of P Frequency of p
1 0.55 0.45
2 0.54 0.46
3 0.57 0.43
4 0.56 0.44
5 0.55 0.45

Which of the following conditions most likely exists within the plant population, based on the Hardy-Weinberg principle?
Net mutations are introduced.
The population is incapable of migrating.
The population size remains fairly small.
Sexual selection is taking place.

The Hardy–Weinberg principle relies on a number of assumptions: (1) random mating (i.e, population structure is absent and matings occur in proportion to genotype frequencies), (2) the absence of natural selection, (3) a very large population size (i.e., genetic drift is negligible), (4) no gene flow or migration, (5) ...

Explanation:

In order for a population to be in Hardy-Weinberg equilibrium, or a non-evolving state, it must meet five major assumptions:

No mutation. No new alleles are generated by mutation, nor are genes duplicated or deleted.

Random mating. ...

No gene flow. ...

Very large population size. ...

No natural selection.

The conditions which maintain his principle are no gene flow, random mating, no mutation, no natural selection, and large population size. So, small population, natural selection, nonrandom mating, mutation, will disrupt Hard-Weinberg. equilibrium

the answer would be 2, if crossing over doesn’t occur 2 out of 4 of the daughter cells will have that allele.

hope this : )