Predict the offspring of a woman who carries but does not have the disorder and a man who does have the disorder

Assuming that the disorder is recessive, the phenotype for someone carrying the disorder would be Bb. Someone who doesn't have the disorder would be BB. Bb x BB = BB, BB, Bb, Bb. 50% would not have the disorder and 50% would be carriers.

Its c 1 carrier female ; 1 normal male; 1 male with disorder 

Yes it is hereditary because of the penis