Choose all the answers that apply.

lupe is a carrier for color blindness. her husband, clifford, is colorblind. if lupe and clifford have four children, theoretical chance would predict

two will be colorblind

one will be a carrier

two will not be colorblind

there is a 50 percent chance a boy will be colorblind

all children will be colorblind

The correct answer is - A, B, C, and D.

Explanation:

Colorblindness is a sex-linked recessive genetic disease. It is present in females only if both X chromosomes are homozygous recessive if only one copy of the recessive gene present female will be considered as a carrier and normal. In males, even one copy of the diseased gene can cause color blindness as they carry one X chromosome.

So kids of Lupa XHXh and Clifford XhY will be formed by gametes XH, Xh and Xh, Y of respective parents. By the cross of these offspring will be XHXh (carrier normal female), XHY( normal male), XhXh ( disease female) and XhY (color blind male).

Thus, the correct answer is option -A, B, C, and D.

c

explanation:

idk

when it is at an intermediate population density