(PLESE HELP ME) If a force of 20.0 N is used to lift a box a distance of 0.5 m, how much work is done? (INCLUDE THE UNIT for work!)

100 J

Explanation:

W = F*d

F = 20 N

d = 0,5

W = 20 * 0,5

W = 10 J

Solution given:

force(f)=20N

distance [d]=0.5m

work done =force ×distance =20×0.5=10joule

answer; i believe that the correct answer is (lung);

the oxygenated blood then leaves the lungs through pulmonary veins, which return it to the left heart, completing the pulmonary cycle. this blood then enters the left atrium, which pumps it through the mitral valve into the left ventricle. from the left ventricle, the blood passes through the aortic valve to the aorta.

deoxygenated blood leaves through the right ventricle through the pulmonary artery. from the right atrium, the blood is pumped through the tricuspid valve (or right atrioventricular valve), into the right ventricle.