It takes 600 J of work to lifta crate straight up but 1,200 Jto pushthat crate up a ramp to the same height. What's the efficiency of the ramp?

50 percent

Explanation:

The efficiency of ramp can be found by using this formula

(Output work/input work)*100.

Amounts of work to lift up = 600j

Amount of work bro take up to same height = 1200j

Efficiency of ramp = (600j/1200j) * 100

= 0.5 x100

= 50 percent

Therefore from the calculations above, the efficiency of this ramp is 50 percent