When 50.0 mL of a 1.00 M solution of Fe(NO3)3 are mixed with 50,0 mL of a 1.00 M solution of NaOH, a precipitate forms. How many moles of precipitate is formed?
Fe(NO3)3(aq) + 3 NaOH(aq) - Fe(OH)3(s) + 3 NaNO3(aq)
A) 0.33 moles
B) 0.017 moles
C) 1.00 mole
D) 0.05 moles