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Adenine (A) = 28%

Cytosine (C) = 22%

Explanation:

The DNA molecule, which is the genetic material that stores or holds information needed by the cell for growth, reproduction etc. Structurally, the DNA is composed of nucleotide subunits, which are of four types namely; Adenine, Guanine, Cytosine, and Thymine etc.

According to Chargaff in his complementary base pairing rule, he states that Adenine will always pair with Thymine (A-T) while Guanine will always pair with Cytosine (G-C). Based on this, Chargaff further stated that the amount of adenine must be equal with that of thymine while that of guanine must be equal to cytosine.

In total, their total amount must be equal to 1 or 100% i.e. (A + T) + (G + C) = 100%. In this question, 22% of Guanine are found in the DNA of a fox. This means that automatically, the percentage of cytosine is 22%. We then calculate the amount of Adenine and Thymine as follows:

(A + T) + (G + C) = 100%

A + T + 22 + 22 = 100

A + T + 44 = 100

A + T = 100 - 44

A + T = 56

Since A = T,

56/2 = 28

Hence, A = 28%, T = 28%

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