If Jennifer is normal (and is not a carrier) but her husband, James, is colorblind, what are the chances of their daughter, Jean, being colorblind?

0

Explanation:

This question involves a single gene coding for sight in humans. The allele for normal vision (C) is dominant over the allele for color blindness (c).

Based on the question, If Jennifer is normal (and is not a carrier) i.e. she has a genotype CC, and her husband, James, is colorblind with genotype cc. Each parent will produce C and c gametes respectively. Using these gametes in a punnet square (see attached image), all of the offsprings will have the genotype Cc, which is phenotypically normal visioned.

Therefore, according to this question, the chance of their daughter being color blind is 0.

i would go with b

cytokinesis occurs after telophase so that eliminates d

and the entire reason for cytokinesis is for cellular reproduction

it's the cell cycle, but cytokines is when the cell divides.

theres 3 stages interphase,mitosis,and cytokines.

interphase prepares the cell for division.

mitosis is the process of dividing the cell,it has 4 parts interphase,anaphase,metaphase,and telophase.

lastly there's cytokines,that's when the cell divides into 2 daughter cells