Based on the data, what is the probability a randomly chosen cell will be observed undergoing cell division? You may use the calculator. A.15% A. 15% B.18% B. 18% C.30% C. 30% D.85% D. 85%

A

Explanation:

The active state of cell division covers the prophase, metaphase, anaphase, and telophase. The total number of observed cells that were undergoing cell division can, thus, be calculated by adding the number of cells in each stage of the cell division.

Total number of cell in division = 20+4+2+4

                = 30

Probability that a randomly chose cell will be undergoing cell division = number of cells in division/total number of cells

     = 30/200

          = 0.15 or 15%

The correct option is, therefore, A.

the father in the first generation probably had the recessive colorblind trait in his x chromosome. if he and his wife both had the colorblind trait, even if she had 1 recessive and 1 dominant, then that trait would be passed on to their kids.

(since you didn't attach the family tree this is just an assumption)