A car moves with an initial velocity of 15 m s-1 and accelerates with constant acceleration 4 m s- 2 for 50 seconds. What is the total distance travelled?

Initia Velocity(u) :- 15m/s

Acceleration(a) :- 4m/s2

Time Taken(t) :- 50 Seconds

{ok a formula is there —->>> s = ut + 1/2 at2(it is ‘t’ square)….. now we will write like this and yeah don’t write this}

We Know,

s = ut + 1/2 at2

s = (15*50 + 1/2 *4*50*50)m

s= (750 + 5000)m

s = 5750 m

Therefore distance traveled is 5750 meters.

Hopefully this helps

Di he'd josh joey jef d of j efj ego if jd d of, if ,cow,coe cud jd lax owxmiw zias max oami jev or mid jd to do du vie do fo jf fo lac i jf ld ld ld ur yr yr t eh el do ht t ur jd ke du ft her kr krvurc