In the Gizmo, what light intensity and CO2 level do you think will maximize the rate of photosynthesis?Experiment: Use the Gizmo to find the ideal conditions for photosynthesis. Use any method you like. List the conditions below. Temperature Light intensity Co2 level Oxygen production 23 oC 79% 570 ppm 51.8 mL/HRevise and repeat: One way to test if you've found the ideal conditions is to change each variable ghtly from the value that you recorded above. If the oxygen production decreases with each change at you make, it is likely you have found the ideal conditions. If a small change causes oxygen produc increase, continue to experiment. Ink and discuss: Think about the process of finding the ideal conditions. A. Why would it be hard to find the ideal light intensity if the temperature were very hot or cold? B. Why would it be hard to find the ideal CO2 level if the light intensity were very low?

Solution :

In Gizmo experiment, when both the intensity of light and carbon dioxide level is high, the rate of photosynthesis will maximize.

A). If the temperature is too hot or cold, it becomes difficult to find the ideal intensity of light because if the temperature is hot, the light intensity will be too high and thus the chlorophyll will get damaged. While if it too low, then it will be difficult for the proper functioning of the cells. And hence the photosynthesis will not take place.

B). It will be considered as a limiting factor if the light intensity is low. With light intensity being low, it will be difficult for the plant for survival and ideal carbon dioxide level will have no role. This amount of carbon dioxide does not help the plant to survive as the light intensity is now a rate limiting factor.

the answer that best describes the relative refractory period in the neuron is the resting membrane potential is restored, but concentrations of sodium and potassium are not restored to their original state.

the refractory period is the time during which another stimulus given to the neuron will not lead to a second potential. thus, because na+ channels are inactivated during this time, additional depolarizing stimuli do not lead to new action potentials.  

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