PLEASE HELP! For each molecule of glucose, glycolysis only makes 2 ATP, the Krebs cycle only makes 2 ATP and the ETC makes 34 ATP. If the suspects had given Jared the 2-deoxyglucose poison, would the decrease in ATP concentration be smaller, the same or larger as when they used cyanide? Explain your answer.
(This is from the cellular respiration gizmos lab)

The decrease in ATP concentration would be larger when 2-deoxyglucose

poison is given alongside cyanide.

This is because 2- deoxyglucose will inhibit the production of ATP in the

cells of the body. This lead to decreased or no ATP being generated.  The

presence of cyanide will also lead to a decrease in the concentration due to

presence of other compounds.

This  subsequently leads to a decrease in the concentration of the ATP

present in the solution. This also enables us to deduce that the decrease in

the ATP concentration would be larger.

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Decrease in ATP concentration be larger.

Explanation:

Decrease in ATP concentration be larger because 2-deoxyglucose poison inhibit glycolysis. Glycolysis is the first step of energy production where glucose break down started. If the first step of ATP production is stopped, no energy will be produced so we can conclude that 2-deoxyglucose poison causes decrease in ATP concentration be larger.

both anaerobic and aerobic respiration use glucose (or other carbohydrates), proteins and lipids to produce atp and nadh. cell uses those energy molecules, obtained from food and   breaks them down during the chemical reactions of respiration. in anaerobic respiration, nadh is regenerated to nad+ by enzymes lactate dehydrogenase (lactate is produced, e.g. in muscle cells) or by alcohol dehydrogenase where ethanol is produced (alcohol fermentation), while in aerobic respiration, electrons from nadh are deposited in the mitochondria to regenerate nad+ (electron transport chain. anaerobic respiration produces 2 atp per molecule of glucose compared to aerobic respiration where about 38 atp molecules are produced.