Suppose a population is carrying a condition controlled by two alleles: a (dominant) and a (recessive). only homozygous individuals that have two copies of the recessive allele have the condition. if the a allele has a frequency of 20%, and the a allele had a frequency of 80%, what percentage of the population will have the condition?

a. 20%
b. 4%
c. 80%
d. 64%

The correct answer is -  B. 4%  Explanation:  As per the given information in the question, the genetic condition is homozygous recessive (aa).   The frequency of dominant (A) and recessive allele (a) are given, which are 20% (that is 0.20) and 80% (0.80) respectively.  According to Hardy-Weinberg Principle - p+q=1 ,  p{2} +2pq+q^{2} =1 Where, p and q denotes frequency of dominant and recessive alleles respectively.   p2 = frequency of homozygous dominant genotype (AA)   q2= frequency of homozygous recessive gentotype (aa)   2pq= frequency of heterozygous genotypes (Aa).   We have given value of - p= 0.80 and q= 0.20   To calculate the frequency of homozygous recessive condition (aa) that is represented by q2- q2 = 0.20 × 0.20 = 0.0400  In percentage -  [0.0400/10000] ×100 = 4% Thus, option B) is the right answer.  

Writing, you can revisit previous parts of the lesson by returning to the course map. be sure to refer to the lab’s student guide, which you can find on the first page of the lab experiment activity

Answer:

the correct answers are;

a. the rock was made from more than one type of material.

e. layers of hot liquids in the rock cooled and solidified at different temperatures.

these are the two options that are related to the statement given above.