The graphic shows the citric acid cycle. A diagram of the citric acid cycle is shown. Acetyl C o A enters the citric acid cycle and combines with a 4-carbon compound to form citric acid. During the citric acid cycle, what happens to acetyl-CoA? It enters the citric acid cycle and gains carbon dioxide to form citric acid, and gains more carbon dioxide through redox reactions to form a 4-carbon molecule. It enters the citric acid cycle and associates with a 4-carbon molecule, forming citric acid, and then through redox reactions regenerates the 4-carbon molecule. It enters glycolysis and associates with a 5-carbon molecule through redox reactions, forming another acetyl-CoA molecule. It enters the citric acid cycle and associates with a 4-carbon molecule, forming a 5-carbon compound, and then through oxidation reactions regenerates the 4-carbon molecule.

In the citric acid cycle, when acetyl-CoA enters the cycle, it associates with a 4-carbon molecule (Oxalacetate), forming citric acid, and then through redox reactions regenerates the 4-carbon molecule (Oxalacetate).

The resumed steps of the Citric acid cycle are as follows,

1) Acetyl CoA joins an oxaloacetate molecule, which is a 4C molecule. They release the CoA group and form a 6C molecule called Citrate.

                      Acetil CoA + Oxalacetato → Citrato + CoA group

2) Citrate turns into an isomere Isocitrate

3) Isocitrate oxidates and release 1 CO₂ molecule, producing an α- ketoglutarate molecule -this is a 5C molecule-. Meanwhile, NAD+ reduces to NADH.

                    Isocitrate + NAD+ → α-cetoglutarate + CO₂ + NADH

4) α-ketoglutarate oxidates and release 1 CO₂ molecule, producing a 4C molecule, which joins a Coenzyme A producing Succinyl-CoA. Meanwhile,  NAD+ reduces to NADH.

          α-cetoglutarate + NAD+ → 4C molecule + CO₂ + NADH

          4C molecule + Coenzyme A → Succinil-CoA

5) CoA from Succinyl-CoA is substituted with a phosphate group, which then forms ATP. The final product is Succinate and ATP

       Succinyl-CoA + Phosphate group + ADP → Succinate + ATP + CoA

6) Succinate oxidizes and forms Fumarate, a 4C molecule. FAD+ forms FAH₂

                     Succinate + FAD+ → Fumarate + FADH₂

7) A water molecule and Fumarate produce Malate, which is another 4C molecule

                                Fumarate + H₂O → Malate

8) Finally, malate oxidizes and oxalacetate regenerates -the initial 4C compound-. NAD+ reduces to NADH.

                     Malato + NAD+ → Oxalacetate + NADH

So, when acetyl-CoA enters the cycle, it associates with a 4-carbon molecule (Oxalacetate), forming citric acid, and then through redox reactions regenerates the 4-carbon molecule (Oxalacetate).

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It enters the citric acid cycle and associates with a 4-carbon molecule, forming citric acid, and then through redox reactions regenerates the 4-carbon molecule.

Explanation:

Acetyl-CoA(2C) associates with oxalacetate(4C) to form citric acid(6C). Then through redox reactions, CO2 molecules result from decarboxylation (COOH becomes R-(R1)CH-R2). And through dehydrogenation H2 molecules are incorporated in NADH+ in FADH2, resulting in the 4-carbon molecule at the beginning (oxalacetate). That's why it's called a cycle(Kreb's cycle or citric acid cycle)

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as the gila monster consumes the eggs or young of the desert cottontail and gambel's quail, thus its main food supply is only accessible for a restricted time duration every year. however, for this, the gila monsters exhibit three adaptations, which elevate their survival rate in the desert condition.  

first, is that they possess huge bodies, and can consume greater concentrations of food during a small period. secondly, they require to feed infrequently as they can accumulate fat in their tails. ultimately, their rate of metabolism is very low, so that they can burn their reservoirs of fat gradually.