A diploid yeast was ABD on one chromosome and abd on the other. The yeast cell underwent meiosis and the four genomes in the resulting tetrad were analyzed and determined to be: ABD, ABD, aBD and abd.
(a) For the moment, focus on the outcome regarding the number of B versus b genes. (Ignore D and d.) What is unexpected, regarding the number of gene types in the meiotic cells? Rationalize how this could have happened, assuming that this outcome had something to do with recombination.
(b) Is there a second "unexpected" outcome, and, if so, what is it? Assume that this second outcome occurred in a process that was linked to the first outcome, which happened with the B/b gene. Explain how they both might have occurred together.
(c) What is the name associated with the outcome: ABD/ABD/aBD/abd?