Tongue-curling in humans is a dominant genetic trait (T). Suppose a man who is heterozygous for tongue-curling marries a woman who is also heterozygous for this trait. Create a Punnett Square. What percentage of the offspring will be phenotypic tongue-curlers? and What is the genotypic ratio (different genotype possibility)

The percentage of the offspring will be phenotypic tongue-curlers is 75% and the genotypic ratio is 1TT : 2Tt : 1tt

Explanation: Since tongue-curling in humans is a dominant genetic trait (T), then non tongue-curling is recessive trait and is represented as (t).

A man and woman who are heterozygous for tongue-curling will have genotype Tt. A cross between two heterozygous individuals will produce four offsprings, Tt x Tt = TT, Tt, Tt and tt.

The genotype ratio is 1TT : 2Tt : 1tt.

Since (T) is dominant, genotypes TT and Tt will manifest phenotypically as tongue-curling, while tt will manifest phenotypically as non tongue-curling.

Since three out of four offsprings are phenotypic tongue-curlers, the percentage of the offspring that are tongue-curlers is 3/4 x 100 = 75%

See the attached punnet square for more information

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"menstrual cycle is a complex cycle that consists of several processes. order of occurrence of steps in menstrual cycle are as follows:

1. high progesterone levels maintain the endometrium lining of the uterus.

2. endometrium lining breaks down and low levels of estrogen stimulate the pituitary to release fsh and lh.

3. fsh and lh stimulates the follicles to develop and the oocyte to produce estrogen.

4. rising estrogen levels suppress fsh production and development of other follicles.

5. a spike in lh causes follicle to rupture.

6. a breakdown of corpus luteum causes progesterone level to drop."