A population of dogs can be either brown or black; the black allele (B) has complete dominance over the brown allele (b). Given a population of 2,000 dogs, 1660 black and 340 brown, determine The frequency of individuals with the dominant phenotype.

The frequency is p=0.911

Explanation: Black allele is dominant over brown. According to the data, there are 1660 black in a population of 2000 dogs. The Hardy-Weinberg Law states that , where:

p is the frequency of the dominant allele;

q is the frequency of the recessive allele;

So, for the dominant allele:

p² =

p = 0.911

Thus, individuals with the dominant phenotype has a frequency of p = 0.911 of happening.

thinking it would be d not too sure but i think it's right

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