A medium was inoculated with 5 x 106 cells/ml of E. coli cells. Following a 1-hour lag, the population grew exponentially for 5 hours, after which the population was 5.4 x 109 cells/ml. Calculate g and k for this growth experiment. (10%)

The value of g = 36

The value of k =

Explanation:

Where,

n = number of generation during the period of exponential growth

b = number bacteria at the end of time

B = number of bacteria at the beginning of time

   =

   =

   = 3.3 × 3.033

n   = 10

Where,

g = generation time

t = duration of exponential growth

n = number of generation

  = ( 1+5) × 60 /10

  = 6 × 60 /10

g = 36

Where,

k = specific growth growth rate

g = generation time

   = 0.301 / 36

k  

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