Suppose that b(t)b(t) measures the number of bacteria living in a colony in a petri dish, where bb is measured in thousands and tt is measured in days. one day, you measure that there are 6,000 bacteria and the per capita growth rate is 3.

To begin your question is incomplete, since it would be missing as many days as you want to pass to reach a certain number of bacteria ...

But I can explain to you that with what you put if you have the complete question in your notebook:

Bacteria are usually grown in petri dishes, which are glass capsules where you generate a perfect medium (culture) with all the necessary nutrients for them to live, grow and reproduce ... The bacteria we are talking about in this problem says that reproduce with an exponential of 3, this means that if there are 6000 bacteria today, we multiply that value by 3 and we already know how many there will be tomorrow (3x6,000 = 18,000), if we continue with the same analysis, the day after tomorrow there will be many more ... why? Because the account you would have to do is tomorrow's value multiplied by 3, that is, 18,000x3 = 54,000 !!!

Explanation:

It is important to know that growth with exponent 3 will always generate that the bacterial multiplication of each day is by 3, on the other hand, this serves to understand the magnitude with which bacteria populations grow, and with the rapidity that they do. .

So as a summary we would have to:

today you have 6,000 bacteria

tomorrow 18,000 bacteria (6,000x3)

the day after tomorrow 54,000 bacteria (18,000x3) ...

In just 3 days the bacteria reached a number of 54,000, now look in your folder what number of days your teacher asked you and continue with the account!

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